5(p^2+4c+20)=

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Solution for 5(p^2+4c+20)= equation:


Simplifying
5(p2 + 4c + 20) = 0

Reorder the terms:
5(20 + 4c + p2) = 0
(20 * 5 + 4c * 5 + p2 * 5) = 0
(100 + 20c + 5p2) = 0

Solving
100 + 20c + 5p2 = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-100' to each side of the equation.
100 + 20c + -100 + 5p2 = 0 + -100

Reorder the terms:
100 + -100 + 20c + 5p2 = 0 + -100

Combine like terms: 100 + -100 = 0
0 + 20c + 5p2 = 0 + -100
20c + 5p2 = 0 + -100

Combine like terms: 0 + -100 = -100
20c + 5p2 = -100

Add '-5p2' to each side of the equation.
20c + 5p2 + -5p2 = -100 + -5p2

Combine like terms: 5p2 + -5p2 = 0
20c + 0 = -100 + -5p2
20c = -100 + -5p2

Divide each side by '20'.
c = -5 + -0.25p2

Simplifying
c = -5 + -0.25p2

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